kemarkious21 kemarkious21
  • 16-02-2021
  • Mathematics
contestada

What are the solutions of the quadratic equation p^2+3p-28=40

Respuesta :

paynehannah0080 paynehannah0080
  • 16-02-2021

Answer:

the answer is  =-3±[tex]\sqrt{281}[/tex]/2

Step-by-step explanation:

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unicorn3125
unicorn3125 unicorn3125
  • 16-02-2021

Answer:

             [tex]\bold{p_1\approx6.88\ ,\qquad p_2\approx-9.88}[/tex]

Step-by-step explanation:

[tex]p^2+3p-28=40\\\\p^2+3p-68=0\\\\a=1\,,\ b=3\,,\ c=-68\\\\\\p=\dfrac{-3\pm\sqrt{3^2-4\cdot1\cdot(-68)}}{2\cdot1}=\dfrac{-3\pm\sqrt{281}}{2}\\\\p_1\approx6.88\ ,\qquad p_2\approx-9.88[/tex]

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