ggunabaalexissage ggunabaalexissage
  • 11-11-2016
  • Physics
contestada

If _H = -60.0kJ and _S = -0.200kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature.

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Greenleafable
Greenleafable Greenleafable
  • 18-11-2016
delta G = delta H - T delta S where T is the Kelvin temperature
delta G is the change in Gibbs Free Energy and must be negative for a spontaneous reaction. Set delta G = 0 (for equilibrium) and solve for T


0 = delta H - T delta S
T delta S = delta H
T(-0.200kJ/K) = -60.0kJ
T(-200J/K) = -60,000J
T = 300K

delta S is negative, so (-T delta S) is positive and G is more positive for higher temperatures
This reaction is spontaneous for temperatures less than 300K.


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