babycakesp12 babycakesp12

14-11-2016
Mathematics

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|-4b - 8| + |-1 - b^2| + 2b^3 ; b= -2

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KeaneNR KeaneNR

14-11-2016

Insert -2 wherever there is a b
|-4(-2) - 8| + |-1 - (-2)^2| + 2(-2)^3

-4(-2)= 8, (-2)^2=4, (-2)^3=-8
|8-8| + |-1 - 4| + 2(-8)

8-8=0, -1-4=-5, 2(-8)= -16
|0| +|-5| - 16

|0|=0, |-5|=5
0+5-16=-9

-9 is your answer

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