devonjohnson85 devonjohnson85

12-03-2021
Mathematics

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A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?

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isaacf1890 isaacf1890

12-03-2021

Answer:

x(x-4)(x+8)

Step-by-step explanation:

Factor.

x(x^2+4x-32)

x(x-4)(x+8)

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