Answer:
The factors are 3, a- 6b and a + 6b
Explanation:
Given
[tex]3a^2 -108b^2[/tex]
Required
The factors
[tex]3a^2 -108b^2 =[/tex]
Factor 3 out
[tex]3a^2 -108b^2 = 3(a^2 - 36b^2)[/tex]
Express 36 as [tex]6^2[/tex]
[tex]3a^2 -108b^2 = 3(a^2 - 6^2*b^2)[/tex]
[tex]3a^2 -108b^2 = 3(a^2 - (6b)^2)[/tex]
Apply difference of two squares
[tex]3a^2 -108b^2 = 3(a - 6b)(a + 6b)[/tex]
So, the factors are 3, a- 6b and a + 6b
