2003yhall16
2003yhall16 2003yhall16
  • 12-03-2021
  • Mathematics
contestada

Find the inverse of square root f(n) = n – 3.
Of(n) = (n + 3)
Of-1 (n) = yn +1
Of-1 (n) = -n° +1
Of-1 (n) = -n3 – 3

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MrRoyal
MrRoyal MrRoyal
  • 17-03-2021

Answer:

[tex]f'(n) = n + 3[/tex]

Step-by-step explanation:

Given

[tex]f(n) = n - 3[/tex]

Required

The inverse

[tex]f(n) = n - 3[/tex]

Replace f(n) with y

[tex]y = n - 3[/tex]

Swap positions of y and n

[tex]n = y - 3[/tex]

Make y the subject

[tex]y = n + 3[/tex]

Replace y with f'(n)

[tex]f'(n) = n + 3[/tex]

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