rfuev6jbnv rfuev6jbnv
  • 12-03-2021
  • Mathematics
contestada

HELP!!!!
The measure of side BC =

HELP The measure of side BC class=

Respuesta :

jimrgrant1 jimrgrant1
  • 12-03-2021

Answer:

D

Step-by-step explanation:

Using the cosine ratio and the exact value

cos45° = [tex]\frac{\sqrt{2} }{2}[/tex] , then

cos45° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{BC}{n}[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex] ( cross- multiply )

2BC = n[tex]\sqrt{2}[/tex] ( divide both sides by 2 )

BC = [tex]\frac{n\sqrt{2} }{2}[/tex] → D

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