Answer:
A multiple of 3 can be written 3n where n is a positive integer.
So 3 consecutive multiples of 3 can be written
3n,3n+3,3n+6
The sum of these is 36
3n+3n+3+3n+6=36
9n+9=36
Divide through by 9
n+1=4
n=3
If n=3 then 3n=9 and the three consecutive multiples of three are 9, 12 and 15 which do indeed total 36
Step-by-step explanation:
Hope it is helpful....
