TheGREYSEA TheGREYSEA

14-03-2021
Mathematics

contestada

CAN SOMEONE PLEASE ME...
If k=
[tex] log_{2}(3) [/tex]
, rewrite
[tex] log_{2}(48) [/tex]
in terms of k.

Respuesta :

14-03-2021

Answer:

Using the inverse formula of the first equation we have: k^2=3

Since 48 is 16 times 3 then 48 = 16k ^ 2

So it becomes log2(16k^2)= 2log2(16k)

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