Answer: 6.38 moles of [tex]O_2[/tex] are needed to react with 2.55 mol of [tex]C_2H_2[/tex]
Explanation:
The balanced chemical reaction for the combustion of ethyne is:
[tex]2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O[/tex]
According to stoichiometry:
2 moles of [tex]C_2H_2[/tex] require = 5 moles of [tex]O_2[/tex]
Thus 2.55 mol of [tex]C_2H_2[/tex] require = [tex]\frac{5}{2}\times 2.55=6.38[/tex] moles of [tex]O_2[/tex]
Thus 6.38 moles of [tex]O_2[/tex] are needed to react with 2.55 mol of [tex]C_2H_2[/tex]
