Answer:
5.47 B.M
Explanation:
✓We were given electronic configuration of argon as [Ar] 3d5.
✓This is a divalent ion. It has atomic number of 25.
✓magnetic moment can be calculated using below expresion
√[n(n+2)] .....................eqn(1)
✓ It has 5 unpaired electrons. Then n= 5
✓ [n(n+2)]
✓ substitute the ( n= 5) into eqn(1)
Then magnetic moment= [n(n+2)]
= [ 5(5+2) ]
= 5.47BM
