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  • 15-04-2021
  • Chemistry
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What volume would 75.0g of oxygen gas occupy

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Аноним Аноним
  • 15-04-2021

Answer:

Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.

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