Answer: [tex]9\pi \ in.^2[/tex]
Step-by-step explanation:
Given
The height of the cylinder is [tex]h=7\ in.[/tex]
The volume of the cylinder is [tex]V=63\pi \ in.^3[/tex]
The volume of the cylinder is the product of area and height
[tex]\Rightarrow V=\pi r^2h\\[/tex]
Insert the values
[tex]\Rightarrow 63\pi =A\times 7\\\\\Rightarrow A=\dfrac{63\pi}{7}\\\\\Rightarrow A=9\pi\ in.^2[/tex]
Thus, the area of the cross-section is [tex]9\pi \ in.^2[/tex]
