Answer:
6n + 12
Step-by-step explanation:
Given an integer n, the 3 consecutive even integers greater than 2n are 2n+2, 2n+4 and 2n+6
Taking their sum;
Sum = (2n+2)+(2n+4)+(2n+6)
Sum = 2n+2n+2n+2+4+6
Sum = 6n + 12
Hence the sum of the 3 consecutive even integers greater than 2n is 6n+12
