kimtamayokk kimtamayokk
  • 12-05-2021
  • Mathematics
contestada

Write the equation in standard form of the circle whose diameter has endpoints of (-2, 4) and (8,-6).

Respuesta :

cwrw238 cwrw238
  • 12-05-2021

Answer:

(x - 3)^2 + (y + 1)^2 = 50.

Step-by-step explanation:

The center of the circle is the midpoint of the diameter

= (-2+8)/2 , (4 - 6)/2

= (3, -1).

The radius^2  can be calculated from one point on the circle ( -2, 4) and the center (3, -1).

The radius^2 =  (-2-3)^2 + (4- -1)^2

= 25 + 25 = 50.

So the equation of the circle

is (x - a)^2 + (y - b)^ = r^2   where (a, b) is center and radius = r.

= (x - 3)^2 + (y + 1)^2 = 50

Answer Link

Otras preguntas

Professionals in these careers strive to enhance quality of life through innovations in technology, health sciences or information, the environment and .
PLEASE HELP can someone draw a quick picture of a volcano, I need it for a diagram and my art skills are trash Please i need it in a few minutes
In the triangle below x=? Round to the nearest tenth.
Under a federal system, citizens have the opportunity to petition how many different levels of government?
Find the slope between (2,10) and (9,1).
3y=2x-9 what could be the other equation
Lee uses the graph of the function f(x) to express His projected earnings at his new job. Which BEST describes what f(x)=40 means in the problem? A) the amount
Find the point-slope equation for the line that passes through the points (-10, -20) and (1, -9). Use the first point in your equation. y-[?] = [ ](x-[ ])
Please help. 10 points and brainliest.
5/6 , 7/18 , 11/24 , 19/36 in descending order