trongkhiem15102002 trongkhiem15102002

14-06-2021
Mathematics

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[tex]\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}[/tex]

Respuesta :

Trancescient Trancescient

14-06-2021

Step-by-step explanation:

[tex]\int _{2.2}^{+\infty \:}\frac{10.648}{x^2}dx = 10.648 \int _{2.2}^{\infty \:}\frac{dx}{x^2}[/tex]

[tex] = - \frac{10.648}{x} | _{2.2}^{ \infty} = 4.84[/tex]

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