rileyrocha48
rileyrocha48 rileyrocha48
  • 14-06-2021
  • Mathematics
contestada

solve the system of equations y=2x-3 and y=x^2-3

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icloudfanboy
icloudfanboy icloudfanboy
  • 14-06-2021

I have attached some answers in the photos below hope you find them useful

Ver imagen icloudfanboy
Ver imagen icloudfanboy
Ver imagen icloudfanboy
Answer Link
VestaHofman VestaHofman
  • 14-06-2021

Answer:

0 and 1

Step-by-step explanation:

Given :

[tex]y= 2x-3\\y=2x^{2} -3[/tex]

Now equate the both equation :

[tex]2x-3=2x^{2} -3[/tex]

2x=2[tex]x^{2}[/tex]

x-[tex]x^{2}[/tex]=0

x(1-x)=0

x=0

1-x=0

x=1

Therefore, x=0,1

Answer Link

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