Answer:
Q = 8608.8 J
Explanation:
Given that,
The mass of ice, m = 34 g
The temperature changes from -2°C to 118°C.
The specific heat of ice, c = 2.11 J/g°C
The heat energy needed,
[tex]Q=mc\delata T\\\\Q=34\times 2.11\times (118-(-2))\\Q=8608.8\ J[/tex]
So, 8608.8 J of energy is needed.
