Answer:
[tex]{ \tt{on \: x - axis : 3}} \\ { \tt{on \: y - axis : 0}} \\ = > \: { \tt{x, \: y}} \\ { \boxed{ \bf{substitute \: for \: x \: and \: y}}} \\ \therefore \: { \boxed{ \bf{answer : } \:{ \tt {(3, \: 0)}}}} \\ \\ { \underline{ \blue{ \tt{⚜becker \: jnr}}}}[/tex]
