Answer: 6 moles of [tex]KClO_3[/tex] will be decomposed.
Explanation:
We are given:
Moles of oxygen gas produced = 9 moles
The chemical equation for the decomposition of [tex]KClO_3[/tex] follows:
[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]
By the stoichiometry of the reaction:
If 3 moles of oxygen gas is produced by 2 moles of [tex]KClO_3[/tex]
So, 9 moles of oxygen gas will be produced by = [tex]\frac{2}{3}\times 9=6mol[/tex] of [tex]KClO_3[/tex]
Hence, 6 moles of [tex]KClO_3[/tex] will be decomposed.
