Answer:
D.
Step-by-step explanation:
f(x) = [tex]\sqrt[3]{4x}[/tex]
g(x) = 2x + 3
[tex]\frac{f}{g}[/tex] (x) = 'f' divided by 'g'
[tex]\frac{\sqrt[3]{4x} }{2x+3}[/tex] Substitute.
x cannot be -[tex]\frac{3}{2}[/tex] because that would create a zero in the denominator.
That's a no-no.
It makes it 'undefined'
