ZJSG09112007
ZJSG09112007 ZJSG09112007
  • 12-07-2021
  • Mathematics
contestada

Solve for all positive values of θ less than 360° ,[tex]3 tan \theta+2 =-1[/tex]

Respuesta :

msm555
msm555 msm555
  • 13-07-2021

[tex]\theta=225°,315°[/tex]

Answer:

Solution given:

[tex]3 tan \theta+2 =-1[/tex]

keeping constant term on one side

[tex]3Tan\theta=-1-2[/tex]

[tex]Tan\theta=-3/3[/tex]

[tex]Tan\theta =-1[/tex]

Since tan is negative in third and fourth quadrant.

[tex]Tan\theta=Tan(180+45),Tan(360-45)[/tex]

[tex]\theta=225°,315°[/tex]

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