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13-07-2021
Chemistry

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Calculate the temperature in k of 3.05 moles of gas occupying 3.70 L at 4.12 atm

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13-07-2021

Answer:

[tex]{ \bf{PV = nRT}} \\ { \tt{(4.12 \times 3700) = 3.05 \times 0.083 \times T }} \\ { \tt{15244 = 0.25315 \: T}} \\ { \tt{T = 6.02 \times {10}^{4} \: kelvin }}[/tex]

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