cameronsvay314 cameronsvay314
  • 13-07-2021
  • Mathematics
contestada


If mZACB = 180°, and m2DCB = 1350,
then mZDCA = [? ]°

If mZACB 180 and m2DCB 1350 then mZDCA class=

Respuesta :

moonowl95014 moonowl95014
  • 13-07-2021

Answer:

m<DCA=45°

Step-by-step explanation:

m<DCA=m<ACB-m<DCB

m<DCA=180°-135°

m<DCA=45°

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