Answer:
1.67g H2CO3 are produced
Explanation:
Based on the reaction:
2NaHCO3 → Na2CO3 + H2CO3
2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3
To solve this question we need to find the moles of Na2CO3 = Moles of H2CO3. With their moles we can find the mass of H2CO3 as follows:
Moles Na2CO3 -Molar mass: 105.99g/mol-
2.86g Na2CO3 * (1mol/105.99g) = 0.02698 moles Na2CO3 = Moles H2CO3
Mass H2CO3 -Molar mass: 62.03g/mol-
0.02698 moles * (62.03g/mol) =
1.67g H2CO3 are produced
