Answer:
Origin = (0, 0)
Gradient or slope:
[tex]{ \tt{slope = \frac{(0 - 3)}{(0 - ( - 2))} }} \\ { \tt{slope = - \frac{3}{2} }}[/tex]
General equation of line:
[tex]{ \bf{y = mx + c}}[/tex]
Consider the origin:
[tex]{ \tt{0 = ( - \frac{3}{2} \times 0) + c }} \\ c = 0[/tex]
Equation of line:
[tex]{ \tt{y = - \frac{3}{2}x }} \\ { \tt{2y = - 3x}}[/tex]
Answer:
-2y+3x=0
Step-by-step explanation:
Slop=(3-0)/(-2-0)=-3/2
(Y-Y1) =m(x-x1)
(y-3) =-3/2(x+2)
-2y+3x=0
