bethanylynn554 bethanylynn554
  • 15-07-2021
  • Mathematics
contestada

Find the period of the function y = 3/2 tan(1/3^x).
А) pi
B) pi/3
C) 3pi
D pi/6

Respuesta :

jimthompson5910 jimthompson5910
  • 15-07-2021

Answer:  3pi   (choice C)

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Explanation:

I'm assuming you meant to say

y = (3/2)*tan( (1/3)x )

If so, then that equation is in the form

y = A*tan(Bx)

The B coefficient is B = 1/3 and it directly ties together to the period T.

T = pi/B

T = pi/(1/3)

T = pi*(3/1)

T = 3pi .... answer is choice C

Side note: This formula only works for tangent and cotangent functions.

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queenmy6678 queenmy6678
  • 15-07-2021
the answer is C 3pi
...
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