gurungangela201
gurungangela201 gurungangela201
  • 13-08-2021
  • Mathematics
contestada

algebra hcf
10xyz and 15y²z²​

Respuesta :

rdilkumari
rdilkumari rdilkumari
  • 13-08-2021

Answer:

5yz

Step-by-step explanation:

1st expression=10xyz

=5*2*x*y*z

2nd expression=15(y)2 (z)2

=5*3*y*y*z*z

therefore H.C.F=5yz

underlines are taking common.

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