jojosiick2
jojosiick2 jojosiick2
  • 11-09-2021
  • Mathematics
contestada

Find the slope of any line perpendicular to the line through ( – 6, 4) and (0,2).
25 POINTS

Respuesta :

Аноним Аноним
  • 11-09-2021
  • (-6,4)
  • (0,2)

[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{2-4}{0+6}[/tex]

[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{-2}{6}[/tex]

[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{-1}{3}[/tex]

Answer Link
mhanifa
mhanifa mhanifa
  • 12-09-2021

Answer:

  • 3

Step-by-step explanation:

Line through ( – 6, 4) and (0,2) has a slope:

  • m₁ = (2 - 4)/(0 - (-6)) = -2/6 = -1/3

The line perpendicular to this has a slope, negative-reciprocal to this:

  • m₂ = -1/m₁ = -1 /(-1/3) = 3
Answer Link

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