Respuesta :

mm5725

Answer:

\frac{\left(x+5\right);p}{\left(x+5\right);}=\frac{2x^2}{\left(x+5\right);}-\frac{6x}{\left(x+5\right);}-\frac{1}{\left(x+5\right);};\quad \:x\ne \:-5p=\frac{2x^2-6x-1}{;\left(5+x\right)};\quad \:x\ne \:-5

Step-by-step explanation:

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