Respuesta :

Answer:

[tex]\pmb{ x=5}[/tex]

Step-by-step explanation:

[tex]\dfrac{2}{7}×(21x-14)=3x+11\\\\\dfrac{2}{7}×7(3x-2)=3x+11\\\\2(3x-2)=3x+11\\\\6x-4=3x+11\\\\6x-3x=11+4\\\\3x=15\\\\x=\dfrac{15}{3}\\\\\boxed{x=\frak{5}} [/tex]

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