holdensamantha2004 holdensamantha2004
  • 14-09-2021
  • Mathematics
contestada

What is the equation in polnt-slope form of the line passing through (-2, 1) and (4, 13)? (1 point)
O a
y-1=-2(x – 4)
Ob
y- 1 = 2(x + 2)
ос
y - 13 = -2(x + 2)
Od
y - 13 = 2(x + 4)

Respuesta :

jimrgrant1 jimrgrant1
  • 14-09-2021

Answer:

b

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (4, 13)

m = [tex]\frac{13-1}{4-(-2)}[/tex] = [tex]\frac{12}{4+2}[/tex] = [tex]\frac{12}{6}[/tex] = 2

Using the point (- 2, 1 )

y - 1 = 2(x - (- 2)) , that is

y - 1 = 2(x + 2) → b

Using the point (4, 13)

y - 13 = 2(x - 4) ← not one of the options

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