hangely136
hangely136
15-09-2021
Mathematics
contestada
Solve the equation
2h^2-5=27
Respuesta :
KayyyDaaBratt
KayyyDaaBratt
15-09-2021
Answer: h= 4, h=-4
step by step-2h^2-5=27
2h^2-5-27=2ℎ2−5−27=0
2h2−5−27=0
2ℎ2−32=0
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