Answer:
c.)
Step-by-step explanation:
=(4c+−3d)(3c+d)
=(4c)(3c)+(4c)(d)+(−3d)(3c)+(−3d)(d)
=12c2+4cd−9cd−3d2
=12c^2−5cd−3d^2
C
(4c-3d)(3c+d)
= 12c^2+4cd-9cd-3d^2
=12c^2-5cd-3d^2
