swagking
swagking
12-01-2015
Mathematics
contestada
square root of 81x to the 4th power
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Аноним
Аноним
12-01-2015
[tex]{ \left( \sqrt { 81x } \right) }^{ 4 }\\ \\ ={ \left[ { \left( 81x \right) }^{ \frac { 1 }{ 2 } } \right] }^{ 4 }\\ \\ ={ \left( 81x \right) }^{ 2 }\\ \\ ={ 81 }^{ 2 }{ x }^{ 2 }\\ \\ =6561{ x }^{ 2 }[/tex]
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