breivogellucy breivogellucy
  • 12-01-2015
  • Mathematics
contestada

solve5(2x-3) = 3(x+4)

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naǫ
naǫ naǫ
  • 12-01-2015
[tex]5(2x-3)=3(x+4) \\ 10x-15=3x+12 \\ 10x-3x=12+15 \\ 7x=27 \\ x=\frac{27}{7}=3 \frac{6}{7}[/tex]
Answer Link
konrad509
konrad509 konrad509
  • 12-01-2015
[tex]5(2x-3) = 3(x+4)\\ 10x-15=3x+12\\ 7x=27\\ x=\dfrac{27}{7}[/tex]
Answer Link

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