Answer:
y=1(x-5)^2+3
Please correct me if i am wrong.
Step-by-step explanation:
We know that the turning point of a graph in the form a(x+p)^2+q is (-p,q) so,
TP(5,3) means that p=-5, q=3.
To solve a for the function y = a(x-5)^2+3, we can substitute one of the points we know lie on the graph for x and y so,
Substitute (8,12) into y=a(x-5)^2+3,
12=a(8-5)^2+3
12=9a+3
9=9a
a=1,
So substitute in a,
y=1(x-5)^2+3
