Answer:
[tex]\frac{t^2-16}{t^2-8t+16}[/tex]
We can factorise the numerator which the difference of squares formula:
[tex]x^2-y^2=(x+y)(x-y)[/tex]
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[tex]\frac{t^2-4^2}{t^2-8t+16} =\frac{(t+4)(t-4)}{t^2-8t+16}[/tex]
Next, factorise the denominator:
[tex]\frac{t^2-4^2}{t^2-8t+16} =\frac{(t+4)(t-4)}{(t-4)^2}[/tex]
[tex]\frac{(t+4)(t-4)}{(t-4)(t-4)}[/tex]
Cancel out the common factor of (t-4):
[tex]\frac{t+4}{t-4}[/tex]
