Respuesta :

SDCInfinity

Answer:

B. [tex]y=\pm\sqrt{x-4}[/tex]

Step-by-step explanation:

Swap the positions of the x and y variables then solve for y again.

[tex]y=x^2+4\\\\x=y^2+4\\\\x-4=y^2+4-4\\\\x-4=y^2\\\\\sqrt{x-4}=\sqrt{y^2}\\\\\pm\sqrt{x-4}=y[/tex]