We need to solve
[tex]\\ \tt\longmapsto (1/3x+2x-5/3x)-(-1/3x+5)[/tex]
[tex]\\ \tt\longmapsto \dfrac{1+6-5}{3}x+1/3x-5[/tex]
[tex]\\ \tt\longmapsto \dfrac{2}{3}x+\dfrac{1}{3}x-5[/tex]
[tex]\\ \tt\longmapsto \dfrac{3}{3}x-5[/tex]
[tex]\\ \tt\longmapsto x-5[/tex]
