nelsonayomide939 nelsonayomide939
  • 15-11-2021
  • Physics
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5 A solid weight 4.8 g in air, 2,8 g in water and 3.2 g in kerosene. The ratio of density of the solid to that of the kerosene is​

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hhapua2002
hhapua2002 hhapua2002
  • 15-11-2021

Answer:

3: 1

Explanation:

When the solid is in air the force acting on it is only its actual weight = Mg

Mg= Vdg

M= mass

v= volume

d=density of solid

g= gravitational acceleration

When in kerosene It's weight and an upthrist acts on it

So what we measure as the apparent weight in kerosene is the difference between its weight and the upthrust

W = weight in kerosene

W= Mg-Vdkg

dk= density of kerosene

Vdkg= Mg - W

d:dk = Vdg: Vdkg

= 4.8 : 4.8-3.2

=4.8: 1.6

=3:1

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