zachrteyeet
zachrteyeet zachrteyeet
  • 11-12-2021
  • Mathematics
contestada

The logarithmic expression [tex]log_{b}(\frac{1}{b^{-b}} )[/tex] where b > 0, is equal to

a) [tex]b^{-b}[/tex]

b) [tex]b^{b}[/tex]

c) [tex]-b[/tex]

d) [tex]b[/tex]

Respuesta :

loneguy
loneguy loneguy
  • 11-12-2021

[tex]\log_b \left(\dfrac 1{b^{-b}}\right)\\\\=\log_b (b^{-b})^{-1}\\\\=\log_b b^b\\\\=b \log_b b\\\\=b \cdot 1\\\\=b[/tex]

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