clairelewallens0ccer
clairelewallens0ccer clairelewallens0ccer
  • 15-12-2021
  • Mathematics
contestada

find the zeros 3x²-6x-45​

Respuesta :

jimrgrant1 jimrgrant1
  • 15-12-2021

Answer:

x = - 3, x = 5

Step-by-step explanation:

To find the zeros equate the expression to zero

3x² - 6x - 45 = 0 ( divide through by 3 )

x² - 2x - 15 = 0

Consider the factors of the constant term (- 15) which sum to give the coefficient of the x- term (- 2)

The factors are - 5 and + 3 , since

- 5 × + 3 = - 15 and - 5 + 3 = - 2 , then

(x - 5)(x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 5 = 0 ⇒ x = 5

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