jarmonlaquasia jarmonlaquasia
  • 13-01-2022
  • Mathematics
contestada

f(x)=(x^5+5)^1/3, find f^-1 (x)

Respuesta :

pradikshyadangol13 pradikshyadangol13
  • 16-01-2022

Answer:

5√(x^1/3-5)

Step-by-step explanation:

hey!

f(x)=(x^5 +5)^1/3

let f(x) be y

y=(x^5 +5)^1/3

now, interchanging x and y

or, x=(y^5 +5)^1/3

or, ∛x= y^5 + 5

or, x^1/3-5=y^5

or, y=5√(x^1/3-5)

therefore f^-1=5√(x^1/3-5)

hope it helps!

thank u!

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