m1isseleycrazyx0 m1isseleycrazyx0

15-01-2017
Chemistry

contestada

At what temperature will 6.21 g of oxygen gas exert a pressure of 5.00 atm in a 10.0-l container?

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AbhiGhost AbhiGhost

15-01-2017

Atomic number of oxygen = 16amu. Moles of Oxygen = 6.21/16 = 0.388 mole. According to ideal gas equation, PV = nRT. T = [tex] \frac{PV}{nR} = \frac{5*10}{0.388*0.082} = 1571.53 K(kelvin)[/tex]. Hope this helps!

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