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15-01-2017
Mathematics

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use Gauss approach to find the sum of the following numbers
1+2+3+4+...+98

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Newtion Newtion

15-01-2017

[tex]\displaystyle 1+2+3+4+...+n= \frac{n(n+1)}{2} [/tex]

According to Gauss's formula, we can get:

[tex]\displaystyle 1+2+3+4+...+98= \frac{98(98+1)}{2}=49\cdot 99=4851[/tex]

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