Respuesta :

[tex] \leadsto \sf \dfrac{p}{9} + 89 = - 103[/tex]

[tex] \\ \\ [/tex]

[tex] \leadsto \sf \dfrac{p}{9} = - 192[/tex]

[tex] \\ \\ [/tex]

[tex] \leadsto \sf p = - 192 \times 9[/tex]

[tex] \\ \\ [/tex]

[tex] \leadsto \sf p = - 1728[/tex]