Respuesta :

Answer:

Step-by-step explanation:

If two chords intersect inside a circle, then

DE * BE =AE * CE

10*x = 8*6

 10x = 48

   x = 48/10

x = 4.8

[tex] \: \sf \: DE \times BE =AE \times CE \\ \\ \sf10 \times x = 8 \times 6 \\ \\ \sf10x = 48 \\ \\ \sf \: x = \dfrac{48}{10} \\ \\ \sf \: x = \cancel\dfrac{48}{10} \\ \\ \sf \red{x = 4.8}[/tex]