Answer:
[tex]\huge\boxed{\sf P =\sqrt{45} }[/tex]
Step-by-step explanation:
Since, the triangle is a right angled triangle, we can use Pythagoras theorem to find the perpendicular of the triangle.
Which is:
[tex](Hypotenuse)^2=(Base)^2+(Perpendicular)^2[/tex]
Rearranging
(Perpendicular)² = (Hypotenuse)² - (Base)²
Where P = ?, H = 7 and B = 2
(P)² = (7)² - (2)²
(P)² = 49 - 4
(P)² = 45
Take sqrt on both sides
[tex]P =\sqrt{45}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
