Respuesta :

indrawboy

%Mass

Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol

[tex]\tt C=\dfrac{4.12}{58}\times 100\%=82.8\%\\\\H=100\%-82.8\%=17.2\%[/tex]

or

[tex]\tt H=\dfrac{10.1}{58}\times 100\%= 17.2\%[/tex]

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